On 14 Apr 2004 19:24:41 -0700, hallian wrote:

> I have two variables for a bash script and somehow not sure how to
> resolve it.... in a short version of lines....
>
> newcity="london cairo newyork"
> oldcity="cairo congo paris london"
>
> Is there a easiser way to find:
> 1) common cities,

If [ $oldcity = $newcity ] ; then
it's common

fi

> 2) unique to newcity
> 3) unique to oldcity

You did not give number of cities to check.
Put new cities into new.txt
Put old cities into common.txt

Now as you get each city, you can grep the txt files to determin which
is which.

hallian wrote:
> hello-
>
> I have two variables for a bash script and somehow not sure how to
> resolve it.... in a short version of lines....
>
> newcity="london cairo newyork"
> oldcity="cairo congo paris london"
>
> Is there a easiser way to find:
> 1) common cities,
> 2) unique to newcity
> 3) unique to oldcity
>
> thanks
> hallian

man comm

--
William Park, Open Geometry Consulting,
Linux solution/training/migration, Thin-client

(I feel like I'm doing somebody's homework assignment)

Here's one way, but it's not easy or short IMHO:

#!/bin/bash

newcity="london cairo newyork"
oldcity="cairo congo paris london"

read -a newcityarray < <(echo $newcity)
read -a oldcityarray < <(echo $oldcity)

typeset -i i=0
typeset -i j
typeset -a common
typeset -a uniqueToNew
typeset -a uniqueToOld

while ((i<${#newcityarray[*]}))
do
j=0
while ((j<${#oldcityarray[*]}))
do
if [[ ${newcityarray[$i]} = ${oldcityarray[$j]} ]]
then
common=(${common[*]} ${oldcityarray[$j]})
fi

((j=j+1))
done
if [[ ${newcityarray[$i]} != ${common[${#common[*]}-1]} ]]
then
uniqueToNew=(${uniqueToNew[*]} ${newcityarray[$i]})
fi
((i=i+1))
done

i=0

while ((i<${#oldcityarray[*]}))
do
j=0
isCommon="FALSE"
while ((j<${#common[*]}))
do
if [[ ${oldcityarray[$i]} = ${common[$j]} ]]
then
isCommon="TRUE"
fi
((j=j+1))
done
if [[ "$isCommon" != "TRUE" ]]
then
uniqueToOld=(${uniqueToOld[@]} ${oldcityarray[$i]})
fi
((i=i+1))
done

echo -e "Common Cities: ${common[*]} \nUnique to new: ${uniqueToNew[*]}"
echo "Unique to old: ${uniqueToOld[*]}"

On Fri, 30 Apr 2004 00:42:57 GMT, news-david.IHATESPAM@wizNOSPAMdoNOTSPAMm.net wrote:
>
> (I feel like I'm doing somebody's homework assignment)

I think so also.


Please bookmark the following, very large,
Frequently Asked Questions (faq) Search engine:

http://groups.google.com/advanced_group_search
oldcity newcity in the first box
*linux* in Newsgroup, U need 2 use *, pick English

Results 1 - 2 of about 4 English messages for oldcity newcity
group:*linux*. (0.23 seconds)