x + x square equal any number ??? - Hewlett Packard

This is a discussion on x + x square equal any number ??? - Hewlett Packard ; 3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234 how can i solve like this questions...can anybody help ??...

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  1. x + x square equal any number ???

    3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234

    how can i solve like this questions...can anybody help ??

  2. Re: x + x square equal any number ???

    On Thu, 6 Nov 2008 22:51:35 -0800 (PST), stndby
    wrote:

    >3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234
    >
    >how can i solve like this questions...can anybody help ??


    On HP 50g: [RightShift] [NUM.SLV] and solve for x.

    Damir

  3. Re: x + x square equal any number ???

    > 3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234
    >
    > how can i solve like this questions...can anybody help ??


    [ 24 0 0 0 0 0 34 5 3 -34234 ] PROOT

    The only real root seems to be about 2.2381

  4. Re: x + x square equal any number ???

    On Nov 7, 1:27*pm, kiy wrote:
    > > 3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234

    >
    > > how can i solve like this questions...can anybody help ??

    >
    > [ 24 0 0 0 0 0 34 5 3 -34234 ] PROOT
    >
    > The only real root seems to be about 2.2381


    More graphical method:

    [RS] NUM.SLV(7) 3. Solve poly...

    Type in the coefficients as a vector in descending order, then move
    the cursor to Roots: and press SOLVE(F6). It returns a vector of the
    roots in the screen, then pushes that vector onto level 1 of the stack
    and labels it "Roots:".

    Use the command OBJ\-> to separate the vector into its entries (in
    this case, so that each root gets its own stack level). The command OBJ
    \-> also returns {9.}, meaning that there were 9 objects in that
    vector. Now it is quick to see that there are 8 complex roots and 1
    real root.


    Of course, kiy's method of entering the coefficients as a vector and
    using the command PROOT is much quicker if you can remember the name
    of the command (which is not that difficult). You can also use the OBJ
    \-> command on the result from PROOT (which is equivalent to the
    NUM.SLV result).

    As an aside, a related command is PEVAL. It takes two arguments: the
    vector of coefficients in descending order in level 2, and the point
    where it is to be evaluated in level 1:

    2: [4 0 0 7 2]
    1: 5
    PEVAL

    is shorthand for evaluating 4x^4 + 7x + 2 at x = 5.

    S.C.

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