3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234

how can i solve like this questions...can anybody help ??

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- 11-07-2008, 06:51 AMunixx + x square equal any number ???
3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234

how can i solve like this questions...can anybody help ??

- 11-07-2008, 09:48 AMunixRe: x + x square equal any number ???
On Thu, 6 Nov 2008 22:51:35 -0800 (PST), stndby <beydursun@gmail.com>

wrote:

[color=blue]

>3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234

>

>how can i solve like this questions...can anybody help ??[/color]

On HP 50g: [RightShift] [NUM.SLV] and solve for x.

Damir

- 11-07-2008, 06:27 PMunixRe: x + x square equal any number ???
> 3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234[color=blue]

>

> how can i solve like this questions...can anybody help ??[/color]

[ 24 0 0 0 0 0 34 5 3 -34234 ] PROOT

The only real root seems to be about 2.2381

- 11-10-2008, 09:37 PMunixRe: x + x square equal any number ???
On Nov 7, 1:27*pm, kiy <k_ak...@hotmail.com> wrote:[color=blue][color=green]

> > 3.x + 5.x^2 + 34.x^3 + 24.x^9 = 34234[/color]

>[color=green]

> > how can i solve like this questions...can anybody help ??[/color]

>

> [ 24 0 0 0 0 0 34 5 3 -34234 ] PROOT

>

> The only real root seems to be about 2.2381[/color]

More graphical method:

[RS] NUM.SLV(7) 3. Solve poly...

Type in the coefficients as a vector in descending order, then move

the cursor to Roots: and press SOLVE(F6). It returns a vector of the

roots in the screen, then pushes that vector onto level 1 of the stack

and labels it "Roots:".

Use the command OBJ\-> to separate the vector into its entries (in

this case, so that each root gets its own stack level). The command OBJ

\-> also returns {9.}, meaning that there were 9 objects in that

vector. Now it is quick to see that there are 8 complex roots and 1

real root.

Of course, kiy's method of entering the coefficients as a vector and

using the command PROOT is much quicker if you can remember the name

of the command (which is not that difficult). You can also use the OBJ

\-> command on the result from PROOT (which is equivalent to the

NUM.SLV result).

As an aside, a related command is PEVAL. It takes two arguments: the

vector of coefficients in descending order in level 2, and the point

where it is to be evaluated in level 1:

2: [4 0 0 7 2]

1: 5

PEVAL

is shorthand for evaluating 4x^4 + 7x + 2 at x = 5.

S.C.