knighttof3@yahoo.com wrote:
> Hi,
> I've a Makefile that looks like this:
> ARCH = ppc
> all: linux app
> linux:
> cd linux && $(MAKE)
>
> My Q is, does this mean that 'ARCH = ppc' flag is passed to the make in
> linux or not? If not, how do I pass it (short of putting $(MAKE)
> $(MAKEFLAGS) or $(MAKE) ARCH=ppc in the rule for 'linux'?)
> I believe $(MAKE) $(MAKEFLAGS) is the wrong construction since it
> translates to 'make -w'. My point is, if user doesn't put any 'ARCH='
> argument while invoking the top-level make, how do I pass ARCH=ppc flag
> to the make in the linux subdirectory?

cd linux && ARCH=$(ARCH) $(MAKE)

will work, to be thorough you ought to check that ARCH has been defined
beforehand

ifndef ARCH
#default
ARCH = ppc
endif

linux:
cd linux && ARCH=$(ARCH) $(MAKE)

Tom